What is -4<x^4+4x^2<21 ?

The solution to -4<x^4+4x^2<21 is -sqrt(3)<x<sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4<x^4+4x^2<21

- 4 < x^{4} + 4 x^{2} < 21

- 3 < x < 3

Interval Notation

(- 3, 3)

Decimal Notation

- 1.73205 \dots < x < 1.73205 \dots

Solution steps

- 4 < x^{4} + 4 x^{2} < 21

a < u < b

then

a < u and u < b

- 4 < x^{4} + 4 x^{2} and x^{4} + 4 x^{2} < 21

- 4 < x^{4} + 4 x^{2} :

True for all

x

x^{4} + 4 x^{2} < 21 : - 3 < x < 3

Combine the intervals

True for all x and - 3 < x < 3

Merge Overlapping Intervals

- 3 < x < 3

22 \cdot 5

x^{2 - 3 x + 18}

\frac{5 x + 6}{7} = 8

x^{4} y^{- 2}

\frac{10 + 40 i}{- 3 + 5 i}