What are the solutions to the equation 2(x^2+11)=40 ?

The solutions to the equation 2(x^2+11)=40 are x=3,x=-3

Find the zeros of 2(x^2+11)=40

The zeros of 2(x^2+11)=40 are x=3,x=-3

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2 (x^{2} + 11) = 40

x = 3, x = - 3

Solution steps

2 (x^{2} + 11) = 40

Divide both sides by

2

x^{2} + 11 = 20

Move

11

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

(- \frac{5}{2})^{3}

\frac{21}{- 3}

- 6 x > - 24

3 x - 3 y

What are the solutions to the equation 2(x^2+11)=40 ?
The solutions to the equation 2(x^2+11)=40 are x=3,x=-3
Find the zeros of 2(x^2+11)=40
The zeros of 2(x^2+11)=40 are x=3,x=-3