What are the solutions to the equation -4x^2+6x-3=0 ?

The solutions to the equation -4x^2+6x-3=0 are x= 3/4-i(sqrt(3))/4 ,x= 3/4+i(sqrt(3))/4

Find the zeros of -4x^2+6x-3=0

The zeros of -4x^2+6x-3=0 are x= 3/4-i(sqrt(3))/4 ,x= 3/4+i(sqrt(3))/4

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- 4 x^{2} + 6 x - 3 = 0

x = \frac{3}{4} - i \frac{3}{4}, x = \frac{3}{4} + i \frac{3}{4}

Solution steps

- 4 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) ( - 3 )}{2 ( - 4 )}

Simplify

6^{2} - 4 (- 4) (- 3) : 23 i

x_{1, 2} = \frac{- 6 \pm 2 3 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 3 i}{2 ( - 4 )}, x_{2} = \frac{- 6 - 2 3 i}{2 ( - 4 )}

x = \frac{- 6 + 2 3 i}{2 ( - 4 )} : \frac{3}{4} - i \frac{3}{4}

x = \frac{- 6 - 2 3 i}{2 ( - 4 )} : \frac{3}{4} + i \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{3}{4}, x = \frac{3}{4} + i \frac{3}{4}

x^{2} - \frac{1}{5} x + \frac{1}{100}

- 3 n (5 n - 1) = 0

(1 + \frac{0.1}{12})^{12} - 1

- x^{2} + 8 x - 6 = 0

- 7 + 4 c = 7 c + 6

What are the solutions to the equation -4x^2+6x-3=0 ?
The solutions to the equation -4x^2+6x-3=0 are x= 3/4-i(sqrt(3))/4 ,x= 3/4+i(sqrt(3))/4
Find the zeros of -4x^2+6x-3=0
The zeros of -4x^2+6x-3=0 are x= 3/4-i(sqrt(3))/4 ,x= 3/4+i(sqrt(3))/4