What are the solutions to the equation -2x^2-5x+5=0 ?

The solutions to the equation -2x^2-5x+5=0 are x=-(5+sqrt(65))/4 ,x=(sqrt(65)-5)/4

Find the zeros of -2x^2-5x+5=0

The zeros of -2x^2-5x+5=0 are x=-(5+sqrt(65))/4 ,x=(sqrt(65)-5)/4

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- 2 x^{2} - 5 x + 5 = 0

x = - \frac{5 + 65}{4}, x = \frac{65 - 5}{4}

Decimal Notation

x = - 3.26556 \dots, x = 0.76556 \dots

Solution steps

- 2 x^{2} - 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 5 = 65

x_{1, 2} = \frac{- ( - 5 ) \pm 65}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 65}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 65}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 65}{2 ( - 2 )} : - \frac{5 + 65}{4}

x = \frac{- ( - 5 ) - 65}{2 ( - 2 )} : \frac{65 - 5}{4}

The solutions to the quadratic equation are:

x = - \frac{5 + 65}{4}, x = \frac{65 - 5}{4}

6 (x - 5)^{3} (7 x + 3)^{4} + (x - 5)^{4} (7 x + 3)^{3}

3 (x + 5)^{2} = 21

\frac{x + 12}{x + 2} \geq 3

4 y^{2} - 16 (- 4)^{2} = 64

3. 2^{1.5}

What are the solutions to the equation -2x^2-5x+5=0 ?
The solutions to the equation -2x^2-5x+5=0 are x=-(5+sqrt(65))/4 ,x=(sqrt(65)-5)/4
Find the zeros of -2x^2-5x+5=0
The zeros of -2x^2-5x+5=0 are x=-(5+sqrt(65))/4 ,x=(sqrt(65)-5)/4