What are the solutions to the equation x^2+4x+7=0 ?

The solutions to the equation x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

Find the zeros of x^2+4x+7=0

The zeros of x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

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x^{2} + 4 x + 7 = 0

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 7 : 23 i

x_{1, 2} = \frac{- 4 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 3 i}{2 \cdot 1}

x = \frac{- 4 + 2 3 i}{2 \cdot 1} : - 2 + 3 i

x = \frac{- 4 - 2 3 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

- 2 x^{2} - 5 x + 5 = 0

6 (x - 5)^{3} (7 x + 3)^{4} + (x - 5)^{4} (7 x + 3)^{3}

3 (x + 5)^{2} = 21

\frac{x + 12}{x + 2} \geq 3

4 y^{2} - 16 (- 4)^{2} = 64

What are the solutions to the equation x^2+4x+7=0 ?
The solutions to the equation x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i
Find the zeros of x^2+4x+7=0
The zeros of x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i