What are the solutions to the equation 49x^2-14x+1=0 ?

The solutions to the equation 49x^2-14x+1=0 are x= 1/7

Find the zeros of 49x^2-14x+1=0

The zeros of 49x^2-14x+1=0 are x= 1/7

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49 x^{2} - 14 x + 1 = 0

x = \frac{1}{7}

Decimal Notation

x = 0.14285 \dots

Solution steps

49 x^{2} - 14 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 49 \cdot 1}{2 \cdot 49}

(- 14)^{2} - 4 \cdot 49 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 14 )}{2 \cdot 49}

\frac{- ( - 14 )}{2 \cdot 49} = \frac{1}{7}

x = \frac{1}{7}

The solution to the quadratic equation is:

x = \frac{1}{7}

1^{\frac{1}{5}}

5 x + 10

\frac{9}{9} \cdot \frac{2}{8} \cdot \frac{3}{7}

77 x^{2} + 139 x + 60

x^{2} - 17 x + 52 = 0

What are the solutions to the equation 49x^2-14x+1=0 ?
The solutions to the equation 49x^2-14x+1=0 are x= 1/7
Find the zeros of 49x^2-14x+1=0
The zeros of 49x^2-14x+1=0 are x= 1/7