What are the solutions to the equation (x+7)^2+1=12 ?

The solutions to the equation (x+7)^2+1=12 are x=sqrt(11)-7,x=-sqrt(11)-7

Find the zeros of (x+7)^2+1=12

The zeros of (x+7)^2+1=12 are x=sqrt(11)-7,x=-sqrt(11)-7

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(x + 7)^{2} + 1 = 12

x = 11 - 7, x = - 11 - 7

Decimal Notation

x = - 3.68337 \dots, x = - 10.31662 \dots

Solution steps

(x + 7)^{2} + 1 = 12

Move

1

to the right side

(x + 7)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 11 : x = 11 - 7

Solve

x + 7 = - 11 : x = - 11 - 7

The solutions to the quadratic equation are:

x = 11 - 7, x = - 11 - 7

4 x^{\frac{1}{3}} \cdot 4 x^{\frac{3}{2}}

5 ∣ w + 4 ∣ - 82 = - 7

(4 x^{3} y^{3})^{3}

- 2 x - 40 = 8 (1 - x)

3 n^{2} + 30 n + 63

What are the solutions to the equation (x+7)^2+1=12 ?
The solutions to the equation (x+7)^2+1=12 are x=sqrt(11)-7,x=-sqrt(11)-7
Find the zeros of (x+7)^2+1=12
The zeros of (x+7)^2+1=12 are x=sqrt(11)-7,x=-sqrt(11)-7