What are the solutions to the equation 64x^2-48x+9=0 ?

The solutions to the equation 64x^2-48x+9=0 are x= 3/8

Find the zeros of 64x^2-48x+9=0

The zeros of 64x^2-48x+9=0 are x= 3/8

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64 x^{2} - 48 x + 9 = 0

x = \frac{3}{8}

Decimal Notation

x = 0.375

Solution steps

64 x^{2} - 48 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 64 \cdot 9}{2 \cdot 64}

(- 48)^{2} - 4 \cdot 64 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 64}

x = \frac{- ( - 48 )}{2 \cdot 64}

\frac{- ( - 48 )}{2 \cdot 64} = \frac{3}{8}

x = \frac{3}{8}

The solution to the quadratic equation is:

x = \frac{3}{8}

6 x^{2} + 36 x

\frac{x - 1}{x} < 2

2 x^{2} + 3 x + 2 = - 3

3^{\frac{2}{5}} \cdot 3^{(- \frac{7}{5})}

\frac{9 !}{7 ! 2 !}

What are the solutions to the equation 64x^2-48x+9=0 ?
The solutions to the equation 64x^2-48x+9=0 are x= 3/8
Find the zeros of 64x^2-48x+9=0
The zeros of 64x^2-48x+9=0 are x= 3/8