What are the solutions to the equation 3w^2-5=-53 ?

The solutions to the equation 3w^2-5=-53 are w=4i,w=-4i

Find the zeros of 3w^2-5=-53

The zeros of 3w^2-5=-53 are w=4i,w=-4i

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3 w^{2} - 5 = - 53

w = 4 i, w = - 4 i

Solution steps

3 w^{2} - 5 = - 53

Move

5

to the right side

3 w^{2} = - 48

Divide both sides by

3

w^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

w = - 16, w = - - 16

- 16 = 4 i

- - 16 = - 4 i

w = 4 i, w = - 4 i

(\frac{3 n p ^{3}}{7 q ^{2}})^{2}

25 n^{2} + 20 n + 4

\frac{1}{2 - 4}

(x - 2)^{2} = 3

\frac{- 2}{i}

What are the solutions to the equation 3w^2-5=-53 ?
The solutions to the equation 3w^2-5=-53 are w=4i,w=-4i
Find the zeros of 3w^2-5=-53
The zeros of 3w^2-5=-53 are w=4i,w=-4i