faktorisieren (4-5x)^3-7(4-5x)^2(x+1)

Lösung

faktorisieren

(4 - 5 x)^{3} - 7 (4 - 5 x)^{2} (x + 1)

- 3 (4 - 5 x)^{2} (4 x + 1)

Schritte zur Lösung

(4 - 5 x)^{3} - 7 (4 - 5 x)^{2} (x + 1)

Klammere gleiche Terme aus

(4 - 5 x)^{2} : (4 - 5 x)^{2} (4 - 5 x - 7 (x + 1))

= (4 - 5 x)^{2} (4 - 5 x - 7 (x + 1))

Schreibe

4 - 5 x - 7 (x + 1)

um:

- 12 x - 3

= (4 - 5 x)^{2} (- 12 x - 3)

Faktorisiere

- 12 x - 3 : - 3 (4 x + 1)

= (4 - 5 x)^{2} (- 3 (4 x + 1))

Apply rule:

a (- b) = - ab

(4 - 5 x)^{2} (- 3 (4 x + 1)) = - (4 - 5 x)^{2} \cdot 3 (4 x + 1)

= - (4 - 5 x)^{2} \cdot 3 (4 x + 1)

= - 3 (4 - 5 x)^{2} (4 x + 1)

f a c t or k^{2} + k

(0 + 4)^{2} + (y + 5)^{2} = 81

5 - \frac{x}{12} = 8

\frac{2}{3} (\frac{1}{6} x - \frac{3}{4}) = - \frac{17}{30}

s im pl i f y (\frac{3 x ^{4}}{2 y ^{3}})^{3}