faktorisieren 125m^4-20n^4

Lösung

faktorisieren

125 m^{4} - 20 n^{4}

5 (5 m^{2} + 2 n^{2}) (5 m^{2} - 2 n^{2})

Schritte zur Lösung

125 m^{4} - 20 n^{4}

Klammere gleiche Terme aus

5 : 5 (25 m^{4} - 4 n^{4})

= 5 (25 m^{4} - 4 n^{4})

Faktorisiere

25 m^{4} - 4 n^{4} : (5 m^{2} + 2 n^{2}) (5 m^{2} - 2 n^{2})

= 5 (5 m^{2} + 2 n^{2}) (5 m^{2} - 2 n^{2})

- \frac{1}{2} (t - 3) + t^{2} = 0

- 0.3 x = 9

x^{2} - 3 x = 0

2 x - 3 = x - 15

9 < 4 x + 1 < x + 16