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受欢迎的代数 >

-1/2 (t-3)+t^2=0

解答

- \frac{1}{2} (t - 3) + t^{2} = 0

解答

t = \frac{1}{4} + i \frac{23}{4}, t = \frac{1}{4} - i \frac{23}{4}

求解步骤

- \frac{1}{2} (t - 3) + t^{2} = 0

在两边乘以

2

- (t - 3) + 2 t^{2} = 0

展开

- (t - 3) + 2 t^{2} : - t + 3 + 2 t^{2}

- t + 3 + 2 t^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

2 t^{2} - t + 3 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

化简

(- 1)^{2} - 4 \cdot 2 \cdot 3 : 23 i

t_{1, 2} = \frac{- ( - 1 ) \pm 23 i}{2 \cdot 2}

将解分隔开

t_{1} = \frac{- ( - 1 ) + 23 i}{2 \cdot 2}, t_{2} = \frac{- ( - 1 ) - 23 i}{2 \cdot 2}

t = \frac{- ( - 1 ) + 23 i}{2 \cdot 2} : \frac{1}{4} + i \frac{23}{4}

t = \frac{- ( - 1 ) - 23 i}{2 \cdot 2} : \frac{1}{4} - i \frac{23}{4}

二次方程组的解是:

t = \frac{1}{4} + i \frac{23}{4}, t = \frac{1}{4} - i \frac{23}{4}

作图

流行的例子

- 0.3 x = 9

x^{2} - 3 x = 0

2 x - 3 = x - 15

9 < 4 x + 1 < x + 16

3 x^{2} - 33 x - 6 = 0