What are the solutions to the equation quadraticformula x^2-9x=10 ?

The solutions to the equation quadraticformula x^2-9x=10 are x=10,x=-1

Find the zeros of quadraticformula x^2-9x=10

The zeros of quadraticformula x^2-9x=10 are x=10,x=-1

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x^{2} - 9 x = 10

x = 10, x = - 1

Solution steps

x^{2} - 9 x = 10

Move

10

to the left side

x^{2} - 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 10) = 11

x_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 1}

x = \frac{- ( - 9 ) + 11}{2 \cdot 1} : 10

x = \frac{- ( - 9 ) - 11}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 10, x = - 1

x, 5^{x} = 55

x, \frac{5}{( x - 5 )} = \frac{x}{( x - 5 )} - \frac{5}{4}

x, 1 - 2 x = 9

x, 4^{x} = 17

(- 7) - (4)

What are the solutions to the equation quadraticformula x^2-9x=10 ?
The solutions to the equation quadraticformula x^2-9x=10 are x=10,x=-1
Find the zeros of quadraticformula x^2-9x=10
The zeros of quadraticformula x^2-9x=10 are x=10,x=-1