sqrt(x-3)× sqrt(2x+2)=x+1

解答

x - 3 \cdot 2 x + 2 = x + 1

x = 7

求解步骤

x - 3 2 x + 2 = x + 1

两边进行平方:

2 x^{2} - 4 x - 6 = x^{2} + 2 x + 1

2 x^{2} - 4 x - 6 = x^{2} + 2 x + 1

解

2 x^{2} - 4 x - 6 = x^{2} + 2 x + 1 : x = 7, x = - 1

x = 7, x = - 1

验证解:

x = 7

真

, x = - 1

假

解是

x = 7

3 8 r + 1 = 3 r + 8

y = \frac{y + 2}{5 - y}

5 x + 14 - x = 8

40 x = 5 x + 3

2 h - 5 = 1 - h - 3