4= x/2+(x-y)/(8+6i)

解答

4 = \frac{x}{2} + \frac{x - y}{8 + 6 i}

x = 8, y = 8

求解步骤

4 = \frac{x}{2} + \frac{x - y}{8 + 6 i}

找到

2, 8 + 6 i

的最小公倍数:

16 + 12 i

乘以最小公倍数=

16 + 12 i

4 (16 + 12 i) = \frac{x}{2} (16 + 12 i) + \frac{x - y}{8 + 6 i} (16 + 12 i)

乘开

64 + 48 i = (10 x - 2 y) + 6 i x

复数仅在实部和虚部均相等时才相等改写为方程组:

[64 = 10 x - 2 y 48 = 6 x]

[64 = 10 x - 2 y 48 = 6 x] : x = 8, y = 8

x = 8, y = 8

(a + i) (2 + bi) = - 6 + 22 i

- \frac{1}{z - i} - z = 0

(x + i y) (- 4 + 7 i) = - 16 + 3 i

z^{2} = 2 z i

(x + y i) - (- 6 + 14 i) = 18 + 2 i