(7+2i)^4=a+ib

解答

(7 + 2 i)^{4} = a + ib

a = 1241, b = 2520

求解步骤

(7 + 2 i)^{4} = a + ib

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(7 + 2 i)^{4} : 1241 + 2520 i

1241 + 2520 i = a + ib

复数仅在实部和虚部均相等时才相等改写为方程组:

[1241 = a 2520 = b]

[1241 = a 2520 = b] : a = 1241, b = 2520

a = 1241, b = 2520

(2 a + 1) (3 + 2 i) + 8 = bi

(1 + i) (x + i y) = 2 - 5 i

\frac{x + i y + 2 + 3 i}{2 x + 2 i y - 3} = i + 2

so l v e f or t, a = v f - \frac{v i}{t}

1.2 x + 3 + y i = 7.2 - 4.3 i