(2+5i)/(1-i)=x+yi

解答

\frac{2 + 5 i}{1 - i} = x + y i

x = - \frac{3}{2}, y = \frac{7}{2}

求解步骤

\frac{2 + 5 i}{1 - i} = x + y i

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\frac{2 + 5 i}{1 - i} : - \frac{3}{2} + \frac{7 i}{2}

- \frac{3}{2} + \frac{7 i}{2} = x + y i

复数仅在实部和虚部均相等时才相等改写为方程组:

[- \frac{3}{2} = x \frac{7}{2} = y]

[- \frac{3}{2} = x \frac{7}{2} = y] : x = - \frac{3}{2}, y = \frac{7}{2}

x = - \frac{3}{2}, y = \frac{7}{2}

so l v e f or a, ∣ a + bi ∣ = 1

so l v e f or a, ∣ a + bi ∣ = 3

i (x) = x^{2} + 4 x + 7

z = 2 e^{i (\frac{π}{3})}

x + i (4 x - y) = 2 + 3 i