ln(x^2+1)=2

Lösung

ln (x^{2} + 1) = 2

x = e^{2} - 1, x = - e^{2} - 1

Dezimale

x = 2.52765 \dots, x = - 2.52765 \dots

Schritte zur Lösung

ln (x^{2} + 1) = 2

Wende die log Regel an

x^{2} + 1 = e^{2}

Löse

x^{2} + 1 = e^{2} : x = e^{2} - 1, x = - e^{2} - 1

x = e^{2} - 1, x = - e^{2} - 1

lo g_{X} (81) = 4

3 lo g_{10} (x) = - 6

ln (x^{2} + 1) = a

lo g_{4} (256) + lo g_{s} (16) = 6

ln (x) = - 2 ln (\frac{1}{3})