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Beliebt Algebra >

log_{10}(2x+1)=-0.5

Lösung

lo g_{10} (2 x + 1) = - 0.5

Lösung

x = \frac{1 - 10}{2 10}

+1

Dezimale

x = - 0.34188 \dots

Schritte zur Lösung

lo g_{10} (2 x + 1) = - 0.5

Wende die log Regel an

2 x + 1 = \frac{1}{10}

Löse

2 x + 1 = \frac{1}{10} : x = \frac{1 - 10}{2 10}

x = \frac{1 - 10}{2 10}

Graph

Beliebte Beispiele

2+log_{10}(1-x)=0

2 + lo g_{10} (1 - x) = 0

3+log_{2}(2x)=log_{2}(17x-5)

3 + lo g_{2} (2 x) = lo g_{2} (17 x - 5)

solvefor x,ln(y)=2ln(x)+2c

so l v e f or x, ln (y) = 2 ln (x) + 2 c

log_{2-x}(2x^2-1)=2

lo g_{2 - x} (2 x^{2} - 1) = 2

log_{e}(x-2)-3log_{e}(2)=2

lo g_{e} (x - 2) - 3 lo g_{e} (2) = 2