解答
a9=17+(9−1)−8
解答
a=3317,a=−331721+331723i,a=−331721−331723i,a=cos(92π)61732+isin(92π)61732,a=cos(98π)61732+isin(98π)61732,a=cos(914π)61732+isin(914π)61732,a=cos(92π)61732−isin(92π)61732,a=cos(94π)61732+isin(94π)61732,a=cos(910π)61732+isin(910π)61732
求解步骤
a9=17+(9−1)−8
化简 17+(9−1)−8:17
用u=a3 和 u3=a9改写方程式u3=17
解 u3=17:u=317,u=3172−1+3i,u=3172−1−3i
u=317,u=3172−1+3i,u=3172−1−3i
代回 u=a3,求解 a
解 a3=317:a=3317,a=−331721+331723i,a=−331721−331723i
解 a3=3172−1+3i:a=cos(92π)61732+isin(92π)61732,a=cos(98π)61732+isin(98π)61732,a=cos(914π)61732+isin(914π)61732
解 a3=3172−1−3i:a=cos(92π)61732−isin(92π)61732,a=cos(94π)61732+isin(94π)61732,a=cos(910π)61732+isin(910π)61732
解为
a=3317,a=−331721+331723i,a=−331721−331723i,a=cos(92π)61732+isin(92π)61732,a=cos(98π)61732+isin(98π)61732,a=cos(914π)61732+isin(914π)61732,a=cos(92π)61732−isin(92π)61732,a=cos(94π)61732+isin(94π)61732,a=cos(910π)61732+isin(910π)61732