8^{x-9}=(1/2)^{x+1}

Lösung

8^{x - 9} = (\frac{1}{2})^{x + 1}

x = \frac{13}{2}

Dezimale

x = 6.5

Schritte zur Lösung

8^{x - 9} = (\frac{1}{2})^{x + 1}

Wende Exponentenregel an

3 (x - 9) = - (x + 1)

Löse

3 (x - 9) = - (x + 1) : x = \frac{13}{2}

x = \frac{13}{2}

3^{5 x} = 12

9^{3 x - 12} = (3)^{2 x}

3^{2 x + 1} = 2 7^{x + 2}

(\frac{1}{9})^{x - 5} = 27

5 = 1 5^{2 - 0.01 q}