mn=a^x

Lösung

mn = a^{x}

x = \frac{ln ( mn )}{ln ( a )}

Schritte zur Lösung

mn = a^{x}

Wende Exponentenregel an

ln (mn) = x ln (a)

Löse

ln (mn) = x ln (a) : x = \frac{ln ( mn )}{ln ( a )}

x = \frac{ln ( mn )}{ln ( a )}

7^{x + 1} + 7^{1 - x} = 50

so l v e f or x, y^{x} = 5

so l v e f or x, y^{x} = 2

2^{2 x - 1} = 64

so l v e f or a, a^{b} = b^{a}