2^x=e^{x+2}

Lösung

2^{x} = e^{x + 2}

x = \frac{2}{ln ( 2 ) - 1}

Dezimale

x = - 6.51778 \dots

Schritte zur Lösung

2^{x} = e^{x + 2}

Wende Exponentenregel an

x ln (2) = x + 2

Löse

x ln (2) = x + 2 : x = \frac{2}{ln ( 2 ) - 1}

x = \frac{2}{ln ( 2 ) - 1}

37.5 = 3^{n}

3^{- 2 b} = \frac{1}{27}

so l v e f or y, x = 1 0^{y} + 4

7^{2 x + 3} \cdot 49 = 7^{4 x}

5 = (2.82)^{t}