5=(2.82)^t

Lösung

5 = (2.82)^{t}

t = \frac{ln ( 5 )}{ln ( 2.82 )}

Dezimale

t = 1.55240 \dots

Schritte zur Lösung

5 = (2.82)^{t}

Wende Exponentenregel an

ln (5) = t ln (2.82)

Löse

ln (5) = t ln (2.82) : t = \frac{ln ( 5 )}{ln ( 2.82 )}

t = \frac{ln ( 5 )}{ln ( 2.82 )}

\frac{4 e ^{3 x} - 5}{e ^{3 x} - 1} = 3

350000 = 400 \cdot (1 - e^{- 0.15 t})

3^{x} + 1 = 3^{5}

3^{x^{2} + x} = 9

so l v e f or t, 2^{t} = \frac{1}{16}