3*2^x=5^{x-1}

Lösung

3 \cdot 2^{x} = 5^{x - 1}

x = \frac{ln ( 15 )}{ln ( 5 ) - ln ( 2 )}

Dezimale

x = 2.95544 \dots

Schritte zur Lösung

3 \cdot 2^{x} = 5^{x - 1}

Wende Exponentenregel an

ln (3) + x ln (2) = (x - 1) ln (5)

Löse

ln (3) + x ln (2) = (x - 1) ln (5) : x = \frac{ln ( 15 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 15 )}{ln ( 5 ) - ln ( 2 )}

5^{2 x + 6} = 1

(x + 3)^{(x + 3)} = 1 1^{6} 0.1 1^{5}

2^{2 x - 6} = 1

\frac{3 π}{2} (8) = x e^{x}

6 \cdot 2^{4 x} = 21