3^x=9^{x+1}

Lösung

3^{x} = 9^{x + 1}

x = - 2

Schritte zur Lösung

3^{x} = 9^{x + 1}

Wende Exponentenregel an

x = 2 (x + 1)

Löse

x = 2 (x + 1) : x = - 2

x = - 2

2 (5 + 3^{x + 1}) = 100

2^{x + 1} = 3 x

10 x - e^{- x} = 0

8^{4 x - 3} = (\frac{1}{16})^{x + 1}

4 e^{- x} = 3 e^{x} + 4