2^x=2500

Lösung

2^{x} = 2500

x = \frac{2 ln ( 50 )}{ln ( 2 )}

Dezimale

x = 11.28771 \dots

Schritte zur Lösung

2^{x} = 2500

Wende Exponentenregel an

x ln (2) = ln (2500)

Löse

x ln (2) = ln (2500) : x = \frac{2 ln ( 50 )}{ln ( 2 )}

x = \frac{2 ln ( 50 )}{ln ( 2 )}

(x - 1)^{x^{2} - 2} = (x - 1)^{2 x + 1}

6 4^{a} = 8^{a + 2}

2^{2 x} = 4^{x + 1}

3^{x + 1} = 5^{2 x - 1}

x \cdot 2^{x} = 1