(x-1)^{x^2-2}=(x-1)^{2x+1}

Lösung

(x - 1)^{x^{2} - 2} = (x - 1)^{2 x + 1}

x = 2, x = 3

Schritte zur Lösung

(x - 1)^{x^{2} - 2} = (x - 1)^{2 x + 1}

Wende Exponentenregel an

(x^{2} - 2) ln (x - 1) = (2 x + 1) ln (x - 1)

Löse

(x^{2} - 2) ln (x - 1) = (2 x + 1) ln (x - 1) : x = 2, x = 3

x = 2, x = 3

6 4^{a} = 8^{a + 2}

2^{2 x} = 4^{x + 1}

3^{x + 1} = 5^{2 x - 1}

x \cdot 2^{x} = 1

2^{x - 1} = \frac{1}{16}