16^{x+3}=64^{2x-1}

Lösung

1 6^{x + 3} = 6 4^{2 x - 1}

x = \frac{9}{4}

Dezimale

x = 2.25

Schritte zur Lösung

1 6^{x + 3} = 6 4^{2 x - 1}

Wende Exponentenregel an

2 (x + 3) = 3 (2 x - 1)

Löse

2 (x + 3) = 3 (2 x - 1) : x = \frac{9}{4}

x = \frac{9}{4}

4^{x + 2} = 3 2^{x}

2^{x} = 0.1

5^{2 x + 1} = 5^{x} + 4

5 \cdot 1 0^{x} = 15

lo g_{10} (1 0^{3 x}) = 12