e^{(x+1)(x-1)}=1

解答

e^{(x + 1) (x - 1)} = 1

x = - 1, x = 1

求解步骤

e^{(x + 1) (x - 1)} = 1

使用指数运算法则

(x + 1) (x - 1) = ln (1)

解

(x + 1) (x - 1) = ln (1) : x = - 1, x = 1

x = - 1, x = 1

so l v e f or x, a^{3} e^{3 x} + 2 e^{- 2 y} = C

3^{x} = - 5

3^{x} = 16

3^{x} = 22

75 = 1 1^{x}