9^{5x+2}=(1/3)^{11-x}

Lösung

9^{5 x + 2} = (\frac{1}{3})^{11 - x}

x = - \frac{5}{3}

Dezimale

x = - 1.66666 \dots

Schritte zur Lösung

9^{5 x + 2} = (\frac{1}{3})^{11 - x}

Wende Exponentenregel an

2 (5 x + 2) = - (11 - x)

Löse

2 (5 x + 2) = - (11 - x) : x = - \frac{5}{3}

x = - \frac{5}{3}

2^{6 l o g_{4} (x)} = 8

2^{2 x} \cdot 2 = 3^{x} \cdot 3^{5}

10 e^{2 n - 10} - 5 = 73

e^{e^{x}} = 3

4 9^{x} = \frac{1}{7}