4^{x+3}=7^{x-1}

解

4^{x + 3} = 7^{x - 1}

x = \frac{ln ( 448 )}{ln ( 7 ) - 2 ln ( 2 )}

十進法表記

x = 10.90890 \dots

解答ステップ

4^{x + 3} = 7^{x - 1}

指数の規則を適用する

(x + 3) ln (4) = (x - 1) ln (7)

解く

(x + 3) ln (4) = (x - 1) ln (7) : x = \frac{ln ( 448 )}{ln ( 7 ) - 2 ln ( 2 )}

x = \frac{ln ( 448 )}{ln ( 7 ) - 2 ln ( 2 )}