solvefor y,y^{-1}=x

解答

求解

y, y^{- 1} = x

y = \frac{1}{x}; x \neq = 0

求解步骤

y^{- 1} = x

整理后得

\frac{1}{y} = x

在两边乘以

y

1 = x y

交换两边

x y = 1

两边除以

x; x \neq = 0

y = \frac{1}{x}; x \neq = 0

\frac{2 x}{x - 2} = \frac{- 4}{2 - x}

0 = \frac{- 9 x}{x ^{2} + 1}

\frac{2 y}{2 y + 5} - \frac{1}{3} = - 1

5 x^{- 2} - 24 x^{- 1} - 5 = 0

\frac{x}{x - 4} = \frac{4}{x - 4} + 4