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受欢迎的代数 >

a(x)=2x^2+9x-2

解答

a (x) = 2 x^{2} + 9 x - 2

解答

x = \frac{- 9 + a + a ^{2} - 18 a + 97}{4}, x = \frac{- 9 + a - a ^{2} - 18 a + 97}{4}

求解步骤

a (x) = 2 x^{2} + 9 x - 2

整理后得

a x = 2 x^{2} + 9 x - 2

交换两边

2 x^{2} + 9 x - 2 = a x

将

a x

para o lado esquerdo

2 x^{2} + 9 x - 2 - a x = 0

改写成标准形式

a x^{2} + b x + c = 0

2 x^{2} + (9 - a) x - 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 9 - a ) \pm ( 9 - a ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

化简

(9 - a)^{2} - 4 \cdot 2 (- 2) : a^{2} - 18 a + 97

x_{1, 2} = \frac{- ( 9 - a ) \pm a ^{2} - 18 a + 97}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- ( 9 - a ) + a ^{2} - 18 a + 97}{2 \cdot 2}, x_{2} = \frac{- ( 9 - a ) - a ^{2} - 18 a + 97}{2 \cdot 2}

x = \frac{- ( 9 - a ) + a ^{2} - 18 a + 97}{2 \cdot 2} : \frac{- 9 + a + a ^{2} - 18 a + 97}{4}

x = \frac{- ( 9 - a ) - a ^{2} - 18 a + 97}{2 \cdot 2} : \frac{- 9 + a - a ^{2} - 18 a + 97}{4}

二次方程组的解是:

x = \frac{- 9 + a + a ^{2} - 18 a + 97}{4}, x = \frac{- 9 + a - a ^{2} - 18 a + 97}{4}

作图

流行的例子

x^2-(a-1)x+25=0

x^{2} - (a - 1) x + 25 = 0

- 1 = 1 - x^{2}

w^{2} - 7 w - 9 = 0

- x^{2} + 8 x - 3 = 0

x = x^{2} + 4