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受欢迎的代数 >

pi=-50+32q-4q^2

解答

π = - 50 + 32 q - 4 q^{2}

解答

q = \frac{- - 16 π + 224 + 32}{8}, q = \frac{- 16 π + 224 + 32}{8}

+1

十进制

q = 2.35239 \dots, q = 5.64760 \dots

求解步骤

π = - 50 + 32 q - 4 q^{2}

交换两边

- 50 + 32 q - 4 q^{2} = π

将

π

para o lado esquerdo

- 50 + 32 q - 4 q^{2} - π = 0

改写成标准形式

a x^{2} + b x + c = 0

- 4 q^{2} + 32 q - 50 - π = 0

使用求根公式求解

q_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 4 ) ( - 50 - π )}{2 ( - 4 )}

3 2^{2} - 4 (- 4) (- 50 - π) = - 16 π + 224

q_{1, 2} = \frac{- 32 \pm - 16 π + 224}{2 ( - 4 )}

将解分隔开

q_{1} = \frac{- 32 + - 16 π + 224}{2 ( - 4 )}, q_{2} = \frac{- 32 - - 16 π + 224}{2 ( - 4 )}

q = \frac{- 32 + - 16 π + 224}{2 ( - 4 )} : \frac{- - 16 π + 224 + 32}{8}

q = \frac{- 32 - - 16 π + 224}{2 ( - 4 )} : \frac{- 16 π + 224 + 32}{8}

二次方程组的解是:

q = \frac{- - 16 π + 224 + 32}{8}, q = \frac{- 16 π + 224 + 32}{8}

作图

流行的例子

1/3 (x+4)^2-1=5

\frac{1}{3} (x + 4)^{2} - 1 = 5

- 2 x^{2} - 3 x + 9 = 0

x^{2} + 7 = 2 x

5 b^{2} - 36 b = 32

(2y-1)^2-(2y-1)y+y^2-7=0

(2 y - 1)^{2} - (2 y - 1) y + y^{2} - 7 = 0