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受欢迎的代数 >

G(x)=7x^2+5x-4

解答

G (x) = 7 x^{2} + 5 x - 4

解答

x = \frac{- 5 + G + G ^{2} - 10 G + 137}{14}, x = \frac{- 5 + G - G ^{2} - 10 G + 137}{14}

求解步骤

G (x) = 7 x^{2} + 5 x - 4

整理后得

G x = 7 x^{2} + 5 x - 4

交换两边

7 x^{2} + 5 x - 4 = G x

将

G x

para o lado esquerdo

7 x^{2} + 5 x - 4 - G x = 0

改写成标准形式

a x^{2} + b x + c = 0

7 x^{2} + (5 - G) x - 4 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 5 - G ) \pm ( 5 - G ) ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

化简

(5 - G)^{2} - 4 \cdot 7 (- 4) : G^{2} - 10 G + 137

x_{1, 2} = \frac{- ( 5 - G ) \pm G ^{2} - 10 G + 137}{2 \cdot 7}

将解分隔开

x_{1} = \frac{- ( 5 - G ) + G ^{2} - 10 G + 137}{2 \cdot 7}, x_{2} = \frac{- ( 5 - G ) - G ^{2} - 10 G + 137}{2 \cdot 7}

x = \frac{- ( 5 - G ) + G ^{2} - 10 G + 137}{2 \cdot 7} : \frac{- 5 + G + G ^{2} - 10 G + 137}{14}

x = \frac{- ( 5 - G ) - G ^{2} - 10 G + 137}{2 \cdot 7} : \frac{- 5 + G - G ^{2} - 10 G + 137}{14}

二次方程组的解是:

x = \frac{- 5 + G + G ^{2} - 10 G + 137}{14}, x = \frac{- 5 + G - G ^{2} - 10 G + 137}{14}

作图

流行的例子

6*x^2+6*x-120=0

6 \cdot x^{2} + 6 \cdot x - 120 = 0

- z^{2} = 4

5 x^{2} + 2 = 2 x

solvefor x,E= 1/2 kx^2

so l v e f or x, E = \frac{1}{2} k x^{2}

solvefor x,t(x)=-x^2+4x-5

so l v e f or x, t (x) = - x^{2} + 4 x - 5