2z^2+20z=0

解

2 z^{2} + 20 z = 0

z = 0, z = - 10

解答ステップ

2 z^{2} + 20 z = 0

解くとthe二次式

z_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 0 = 20

z_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 2}

解を分離する

z_{1} = \frac{- 20 + 20}{2 \cdot 2}, z_{2} = \frac{- 20 - 20}{2 \cdot 2}

z = \frac{- 20 + 20}{2 \cdot 2} : 0

z = \frac{- 20 - 20}{2 \cdot 2} : - 10

二次equationの解:

z = 0, z = - 10