erweitern (4x)*(x^2+2xδ+δ^2-4)

Lösung

erweitern

(4 x) \cdot (x^{2} + 2 x δ + δ^{2} - 4)

4 x^{3} + 8 δ x^{2} + 4 δ^{2} x - 16 x

Schritte zur Lösung

(4 x) (x^{2} + 2 x δ + δ^{2} - 4)

= (4 x) (x^{2} + 2 δ x + δ^{2} - 4)

Setze Klammern

= (4 x) x^{2} + (4 x) \cdot 2 x δ + (4 x) δ^{2} + (4 x) (- 4)

Wende Minus-Plus Regeln an

+ (- a) = - a

= x^{2} (4 x) + 2 δ x (4 x) + δ^{2} (4 x) - 4 (4 x)

Vereinfache

x^{2} (4 x) + 2 δ x (4 x) + δ^{2} (4 x) - 4 (4 x) : 4 x^{3} + 8 δ x^{2} + 4 δ^{2} x - 16 x

= 4 x^{3} + 8 δ x^{2} + 4 δ^{2} x - 16 x

e x p an d (2 x + y + 3) \cdot ln (2 x + y + 3)

e x p an d - \frac{1}{s ( s ^{2} + 9 )}

e x p an d - \frac{1}{2 ( e ^{y} + 1 ) ^{2}}

e x p an d \frac{( h + 1 ) ^{2} ( h + 2 ) ^{2}}{4}

e x p an d \frac{3 ( x - 2 )}{x - 3}