展开-1^2-2

解答

展开

- 1^{2} - 2

- 3

求解步骤

- 1^{2} - 2

使用法则

1^{a} = 1

1^{2} = 1

= - 1 - 2

数字相减:

- 1 - 2 = - 3

= - 3

e x p an d \frac{- x + 4}{6 ( x + 2 )}

\frac{d ^{2}}{d x ^{2}} ((y) (3 x - 4))

e x p an d 3 x (2 e^{x - 5 y} y - 5 e^{x - 5 y} y^{2})

e x p an d (2 x - y + 3 z = 10) \cdot (- 3)

e x p an d 1 - (\frac{4}{( x + 1 ) ^{2}})