What are the solutions to the equation x^2-2x+10=0 ?

The solutions to the equation x^2-2x+10=0 are x=1+3i,x=1-3i

Find the zeros of x^2-2x+10=0

The zeros of x^2-2x+10=0 are x=1+3i,x=1-3i

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x^{2} - 2 x + 10 = 0

x = 1 + 3 i, x = 1 - 3 i

Solution steps

x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 10 : 6 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 6 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

- 96

- x^{2} + x + 6 = 0

5 i^{2}

\frac{5 x - 9}{4} - \frac{3 x + 5}{4} = \frac{2}{3}

\frac{8}{18}

What are the solutions to the equation x^2-2x+10=0 ?
The solutions to the equation x^2-2x+10=0 are x=1+3i,x=1-3i
Find the zeros of x^2-2x+10=0
The zeros of x^2-2x+10=0 are x=1+3i,x=1-3i