Solution
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For the solutions are
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The solutions to the quadratic equation are:
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What are the solutions to the equation (x-2)^2=28 ?
The solutions to the equation (x-2)^2=28 are x=2sqrt(7)+2,x=-2sqrt(7)+2Find the zeros of (x-2)^2=28
The zeros of (x-2)^2=28 are x=2sqrt(7)+2,x=-2sqrt(7)+2