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Beliebt Algebra >

270= n/(2[2x^{10)+(n-1)5]}

Lösung

270 = \frac{n}{2 [ 2 x ^{10} + ( n - 1 ) 5 ]}

Lösung

x = 10 \frac{- 2699 n + 2700}{1080}, x = - 10 \frac{- 2699 n + 2700}{1080}

Schritte zur Lösung

270 = \frac{n}{2 [ 2 x ^{10} + ( n - 1 ) \cdot 5 ]}

Multipliziere beide Seiten mit

[2 x^{10} + (n - 1) 5]

270 [2 x^{10} + (n - 1) \cdot 5] = \frac{n}{2}

Löse

270 [2 x^{10} + (n - 1) \cdot 5] = \frac{n}{2} : x = 10 \frac{- 2699 n + 2700}{1080}, x = - 10 \frac{- 2699 n + 2700}{1080}

x = 10 \frac{- 2699 n + 2700}{1080}, x = - 10 \frac{- 2699 n + 2700}{1080}

Graph

Beliebte Beispiele

7/(5*(-7x^2+2)^2)= 5/7

\frac{7}{5 \cdot ( - 7 x ^{2} + 2 ) ^{2}} = \frac{5}{7}

(2x)/(3x+6)= 3/2

\frac{2 x}{3 x + 6} = \frac{3}{2}

solvefor x,f=({x})/((1+{x\))}

so l v e f or x, f = \frac{{ x }}{( 1 + { x } )}

1/x-1/((x+b))= 1/a-1/((a+b))

\frac{1}{x} - \frac{1}{( x + b )} = \frac{1}{a} - \frac{1}{( a + b )}

solvefor l,z=((1+l))/(((3+l)^2))

so l v e f or l, z = \frac{( 1 + l )}{( ( 3 + l ) ^{2} )}