1.1111=1.015^n

Lösung

1.1111 = 1.01 5^{n}

n = \frac{ln ( 1.1111 )}{ln ( 1.015 )}

Dezimale

n = 7.07591 \dots

Schritte zur Lösung

1.1111 = 1.01 5^{n}

Wende Exponentenregel an

ln (1.1111) = n ln (1.015)

Löse

ln (1.1111) = n ln (1.015) : n = \frac{ln ( 1.1111 )}{ln ( 1.015 )}

n = \frac{ln ( 1.1111 )}{ln ( 1.015 )}

so l v e f or n, s = r \frac{( ( 1 + i ) ^{n} - 1 )}{i}

9^{x} = 4

9^{x} = 9

2^{[x] + [x - 2]} = 16

so l v e f or a, a^{a} + 5 = b^{b} + a^{a} - 2^{2}