What are the solutions to the equation 12-5x^2=0 ?

The solutions to the equation 12-5x^2=0 are x=(2sqrt(3))/(sqrt(5)),x=-(2sqrt(3))/(sqrt(5))

Find the zeros of 12-5x^2=0

The zeros of 12-5x^2=0 are x=(2sqrt(3))/(sqrt(5)),x=-(2sqrt(3))/(sqrt(5))

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12 - 5 x^{2} = 0

x = \frac{2 3}{5}, x = - \frac{2 3}{5}

Decimal Notation

x = 1.54919 \dots, x = - 1.54919 \dots

Solution steps

12 - 5 x^{2} = 0

Move

12

to the right side

- 5 x^{2} = - 12

Divide both sides by

- 5

x^{2} = \frac{12}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{12}{5}, x = - \frac{12}{5}

\frac{12}{5} = \frac{2 3}{5}

- \frac{12}{5} = - \frac{2 3}{5}

x = \frac{2 3}{5}, x = - \frac{2 3}{5}

\frac{2}{3} - \frac{16}{3}

31 + j = - 14

\frac{1}{2} (11.8)^{2}

4 n^{2} - 17 n + 4

- 3 (x - 4) = 9 x

What are the solutions to the equation 12-5x^2=0 ?
The solutions to the equation 12-5x^2=0 are x=(2sqrt(3))/(sqrt(5)),x=-(2sqrt(3))/(sqrt(5))
Find the zeros of 12-5x^2=0
The zeros of 12-5x^2=0 are x=(2sqrt(3))/(sqrt(5)),x=-(2sqrt(3))/(sqrt(5))