What is factor 4n^2-17n+4 ?

The solution to factor 4n^2-17n+4 is (4n-1)(n-4)

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factor 4n^2-17n+4

factor

4 n^{2} - 17 n + 4

(4 n - 1) (n - 4)

Solution steps

4 n^{2} - 17 n + 4

Break the expression into groups

= (4 n^{2} - n) + (- 16 n + 4)

Factor out

n

from

4 n^{2} - n : n (4 n - 1)

Factor out

- 4

from

- 16 n + 4 : - 4 (4 n - 1)

= n (4 n - 1) - 4 (4 n - 1)

Factor out common term

4 n - 1

= (4 n - 1) (n - 4)

- 3 (x - 4) = 9 x

3 x - 2 = 16

\frac{( \frac{3}{7} ) ^{4} ( \frac{3}{7} ) ^{3}}{( \frac{3}{7} ) ^{2}}

m^{2} - \frac{25}{2} m = \frac{5}{2}

3 a^{- 5}