What is (-10k^2)/(21)*(-6k^4)/(25) ?

The solution to (-10k^2)/(21)*(-6k^4)/(25) is (4k^6)/(35)

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simplify (-10k^2)/(21)*(-6k^4)/(25)

simplify

\frac{- 10 k ^{2}}{21} \cdot \frac{- 6 k ^{4}}{25}

\frac{4 k ^{6}}{35}

Solution steps

\frac{- 10 k ^{2}}{21} \cdot \frac{- 6 k ^{4}}{25}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 10 k ^{2}}{21} = - \frac{10 k ^{2}}{21}

= - \frac{10 k ^{2}}{21} \cdot \frac{- 6 k ^{4}}{25}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 6 k ^{4}}{25} = - \frac{6 k ^{4}}{25}

= - \frac{10 k ^{2}}{21} (- \frac{6 k ^{4}}{25})

Apply rule:

- a (- b) = ab

- \frac{10 k ^{2}}{21} (- \frac{6 k ^{4}}{25}) = \frac{10 k ^{2}}{21} \cdot \frac{6 k ^{4}}{25}

= \frac{10 k ^{2}}{21} \cdot \frac{6 k ^{4}}{25}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{10 k ^{2} \cdot 6 k ^{4}}{21 \cdot 25}

Cancel

\frac{10 k ^{2} \cdot 6 k ^{4}}{21 \cdot 25} : \frac{2 k ^{2} \cdot 2 k ^{4}}{7 \cdot 5}

= \frac{2 k ^{2} \cdot 2 k ^{4}}{7 \cdot 5}

Simplify

2 k^{2} \cdot 2 k^{4} : 4 k^{6}

= \frac{4 k ^{6}}{7 \cdot 5}

Multiply the numbers:

7 \cdot 5 = 35

= \frac{4 k ^{6}}{35}

9 x^{2} = 8 x

3 x - 8 \geq 7

\frac{x}{8} > 3

- (- \frac{5}{6})^{2}

4 (x - 3) = 9

What is (-10k^2)/(21)*(-6k^4)/(25) ?
The solution to (-10k^2)/(21)*(-6k^4)/(25) is (4k^6)/(35)