faktorisieren x^2y^2+x^2-y^2-1

Lösung

faktorisieren

x^{2} y^{2} + x^{2} - y^{2} - 1

(y^{2} + 1) (x + 1) (x - 1)

Schritte zur Lösung

x^{2} y^{2} + x^{2} - y^{2} - 1

= (x^{2} y^{2} + x^{2}) + (- y^{2} - 1)

Klammere

x^{2}

aus

x^{2} y^{2} + x^{2}

aus

: x^{2} (y^{2} + 1)

Klammere

- 1

aus

- y^{2} - 1

aus

: - (y^{2} + 1)

= x^{2} (y^{2} + 1) - (y^{2} + 1)

Klammere gleiche Terme aus

(y^{2} + 1) : (y^{2} + 1) (x^{2} - 1)

= (y^{2} + 1) (x^{2} - 1)

Faktorisiere

x^{2} - 1 : (x + 1) (x - 1)

= (y^{2} + 1) (x + 1) (x - 1)

e x p an d (2 x - 8)^{3}

s im pl i f y \frac{( \frac{2}{x} + \frac{4}{y} )}{( 2 x + y )}

f (x) = \frac{( x + 1 + 1 - x )}{x}

f a c t or a^{2} - x^{2} + 2 x - 1

s im pl i f y (5.6 f \cdot 42) + (\frac{50000}{c}) - (0.1234 \cdot 1024)