What are the solutions to the equation (11w+5)(6w-18)=0 ?

The solutions to the equation (11w+5)(6w-18)=0 are w=-5/11 ,w=3

Find the zeros of (11w+5)(6w-18)=0

The zeros of (11w+5)(6w-18)=0 are w=-5/11 ,w=3

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(11 w + 5) (6 w - 18) = 0

w = - \frac{5}{11}, w = 3

Solution steps

(11 w + 5) (6 w - 18) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

11 w + 5 = 0 or 6 w - 18 = 0

Solve

11 w + 5 = 0 : w = - \frac{5}{11}

Solve

6 w - 18 = 0 : w = 3

The solutions to the quadratic equation are:

w = - \frac{5}{11}, w = 3

3 x^{2} - 4 x + 16 = 0

2 C - (- 5 C) = - (- 3 C)

- 2 (4 - x) = 6 (x + 2) + 3 x

4 x^{2} - 21 x - 18 = 0

(h - 6) (8 h - 1) = 0

What are the solutions to the equation (11w+5)(6w-18)=0 ?
The solutions to the equation (11w+5)(6w-18)=0 are w=-5/11 ,w=3
Find the zeros of (11w+5)(6w-18)=0
The zeros of (11w+5)(6w-18)=0 are w=-5/11 ,w=3