What are the solutions to the equation X^2+2X-5=0 ?

The solutions to the equation X^2+2X-5=0 are X=-1+sqrt(6),X=-1-sqrt(6)

Find the zeros of X^2+2X-5=0

The zeros of X^2+2X-5=0 are X=-1+sqrt(6),X=-1-sqrt(6)

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X^{2} + 2 X - 5 = 0

X = - 1 + 6, X = - 1 - 6

Solution steps

X^{2} + 2 X - 5 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

X_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, X_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

X = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

X = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

X = - 1 + 6, X = - 1 - 6

- x^{2} - 5 x - 6

lo g_{3} (48) - 2 lo g_{3} (4)

0.05 x + 0.06 (30000 - x) = 1680

2 x^{2} - 7 x + 7 = 0

m^{2} - 12 m + 11

What are the solutions to the equation X^2+2X-5=0 ?
The solutions to the equation X^2+2X-5=0 are X=-1+sqrt(6),X=-1-sqrt(6)
Find the zeros of X^2+2X-5=0
The zeros of X^2+2X-5=0 are X=-1+sqrt(6),X=-1-sqrt(6)