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受欢迎的代数 >

2x^2+bx=-2

解答

2 x^{2} + b x = - 2

解答

x = \frac{- b + b ^{2} - 16}{4}, x = \frac{- b - b ^{2} - 16}{4}

求解步骤

2 x^{2} + b x = - 2

将

2

para o lado esquerdo

2 x^{2} + b x + 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- b \pm b ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

化简

b^{2} - 4 \cdot 2 \cdot 2 : b^{2} - 16

x_{1, 2} = \frac{- b \pm b ^{2} - 16}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- b + b ^{2} - 16}{2 \cdot 2}, x_{2} = \frac{- b - b ^{2} - 16}{2 \cdot 2}

x = \frac{- b + b ^{2} - 16}{2 \cdot 2} : \frac{- b + b ^{2} - 16}{4}

x = \frac{- b - b ^{2} - 16}{2 \cdot 2} : \frac{- b - b ^{2} - 16}{4}

二次方程组的解是:

x = \frac{- b + b ^{2} - 16}{4}, x = \frac{- b - b ^{2} - 16}{4}

作图

流行的例子

3 x^{2} - 8 x - 17 = 0

7 x^{2} - 12 x = 0

6 v^{2} - 45 = 3 v

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5t^2+1.3t-0.7=0

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